A porter lifts a luggage of 15 kg from the ground and puts it on his head 1.5 metre above the ground. calculate the work done on the luggage.
hi friends
I wanted to ask if we have to take the magnitude of g as 9.8 or 10
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As per your question, I am solving this question with two values of 'g' i.e. 9.8 m/s^2 and 10 m/s^2.
In first case:-
Mass (m) = 15 kg
Acceleration due to Gravity (g) = 10 m/s^2
Height (h) = 1.5 m
Work = mgh
=> W = (15 x 10 x 1.5) Joules
=> W = 225 Joules
Now In second case,
Mass (m) = 15 kg
Acceleration due to Gravity (g) = 9.8 m/s^2
Height (h) = 1.5 m
Work = mgh
=> W = (15 x 9.8 x 1.5) Joules
=> W = 220.5 Joules
Be Brainly
In first case:-
Mass (m) = 15 kg
Acceleration due to Gravity (g) = 10 m/s^2
Height (h) = 1.5 m
Work = mgh
=> W = (15 x 10 x 1.5) Joules
=> W = 225 Joules
Now In second case,
Mass (m) = 15 kg
Acceleration due to Gravity (g) = 9.8 m/s^2
Height (h) = 1.5 m
Work = mgh
=> W = (15 x 9.8 x 1.5) Joules
=> W = 220.5 Joules
Be Brainly
Answered by
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Answer:
The work done by porter on the luggage is 225 J
Explanation:
Given,
A porter lifts a luggage of mass = 15 kg from the ground.
It's on his head 1.5 m above the ground.
To find: The work done by him on the luggage
Solution:
here, Force is due to the weight of the luggage.
i.e F = mg , where m = mass of luggage and g = accerleration due to gravity
or, F = 15 * 10 = 150 N
Work done can be given as:
W = F * s
where, F = force and s = displacement i.e 1.5 m
W = 150 * 1.5 = 225 J
Therefore, The work done by porter on the luggage is 225 J.
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