Question

A positive charge of 17.7 microcoulomb is placed at the centre of hollow sphere of radius 15 cm find the electric flux through the surface of the sphere

Answer 1

Final Answer : 17.7uC/£
where £ is permitivity in given medium.

By Gauss's Law,
The Electric field due to any closed surface is equal to the net charge enclosed inside the surface divided by permitivity in given medium.

So, here flux will be Net charge by Permituvity in vacuum.

Therefore, flux will be 1/£ times net charge enclosed inside.

Answer 2

Answer:

We can find through the surface of the sphere by using the formulae of q/ε. Here, the value of charge will be 17.7*10^-6 and the value of ε will be 8.85*10^-12.

Thus, placing the values in the equation we will get the value of flux will be 2*10^6 v/m.

Thus, the value of the electric flux through the hollow sphere will be 2*10^6 v/m.