Physics, asked by Sonalkushwaha76, 27 days ago


A positive charge of 17.7 uC is placed at the centre of a hollow sphere of radius 0.5 m. Calculate the
flux density through the surface of the sphere.

Answers

Answered by hani61
3

Answer:

flux density formula :- ∅/A

∅=q/E⁰

therefore from given values 17.7×10^-6/8.8×10^-12×4π0.5^2

flux density= 6.35×10^5 N/C

Answered by zinaldjoshi
1

Answer:

hope it will be helpful.

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