Question

A positive integer n when divided by 9 gives 7 as remainder

Answer 1

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$\small\bf\red{Step\:By\:Step\: Explanation!!}$

✍️Given A positive integer n is divided by 9 gives 7 as the remainder.

✍️ Let a be quotient

✍️n = 9a+7 3n-1 is divided by 9 now, 3n-1= 3(9a+7)-1 =27a + 21-1

✍️=27a +20 = 27 a + 18 + 2 = 9( 3a + 6) + 2 ✍️when divided by 9 Remainder = ☑️2☑️.

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Answer 2

StepByStepExplanation!!

✍️Given A positive integer n is divided by 9 gives 7 as the remainder.

✍️ Let a be quotient

✍️n = 9a+7 3n-1 is divided by 9 now, 3n-1= 3(9a+7)-1 =27a + 21-1

✍️=27a +20 = 27 a + 18 + 2 = 9( 3a + 6) + 2

✍️when divided by 9 Remainder = ☑️2☑️.

HOPE YOU WILL LIKE MY ANSWER.. :)