Question

A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number. find the two numbers.
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Answer 1

Given, A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.

• To find, Required two numbers

Solution :

According to the first condition

A positive number is 5 times to another number.

→ First number = 5 × 2nd number

• Consider the first number be 5x and 2nd number be x

According to the second condition

If 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.

• First number = 5x + 21
• Second number = x + 21

→ 5x + 21 = 2(x + 21)

→ 5x + 21 = 2x + 42

→ 5x - 2x = 42 - 21

→ 3x = 21

→ x = 21/3

→ x = 7

•°• First number = 5x = 5 × 7 = 35

•°• Second number = x = 7

• Required numbers are 35 and 7

Answer 2

Given :-

A positive number is 5 times to another number. if 21 is added to both the numbers,then one of the new numbers becomes twice the another new number.

To Find :-

Two numbers

Solution :-

Let the number be x

Another number will be 5 × x = 5x

Now

$\sf 5x+21=2(x+21)$

$\sf 5x + 21=2x+42$

$\sf 2x-5x = 21-42$

$\sf -3x=-21$

$\sf x = \dfrac{-21}{-3}$

$\sf x = 7$

Hence,

First number = 7

Second number = 5 × 7 = 35