Question

a positive number is divided into two parts such that the sum of the squares of the two parts is 20 the square of the larger part is 8 times the smaller part taking x as a smaller part of the two parts find the number .

plzzz help me it's urgent​

Answer 1

Answer:

given smaller part = x

(larger part)² = 8x

sum of the squares of the two parts = 20

8x+ x²= 20

x² +8x-20=0

⇒x² +10x-2x-20=0

⇒x(x+10) -2(x+10)=0

⇒(x+10)(x-2)=0

∴x+10=0 or x-2 =0

x= -10 or x=2

we take positive value

i) the required numbers

x= 2

larger number =√8x

= √8*2

= √16

= 4 

Hope it helps you...