Question

A positive number is5 times of another number. if 21 added to both the numbers becomes twice.the other new number. what are the numbers​

Answer 1

Answer:

PLS MARK ME AS BRANLIEST BELOW IS THE SOLUTION

Step-by-step explanation:

Let the No.1 = x

Let the No.1 = xThen the second no. No.2 = 5x.

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.i.e., 2(x + 21) = 5x + 21

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.i.e., 2(x + 21) = 5x + 21 or 2x + 42 = 5x + 21

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.i.e., 2(x + 21) = 5x + 21 or 2x + 42 = 5x + 21Transposing 2x to the RHS and 21 to the LHS:

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.i.e., 2(x + 21) = 5x + 21 or 2x + 42 = 5x + 21Transposing 2x to the RHS and 21 to the LHS: 21 = 5x - 2x = 3x

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.i.e., 2(x + 21) = 5x + 21 or 2x + 42 = 5x + 21Transposing 2x to the RHS and 21 to the LHS: 21 = 5x - 2x = 3xor x = 7

Let the No.1 = xThen the second no. No.2 = 5x.Now the question states that if we add 21 to both numbers one number becomes twice of the other.i.e., 2(x + 21) = 5x + 21 or 2x + 42 = 5x + 21Transposing 2x to the RHS and 21 to the LHS: 21 = 5x - 2x = 3xor x = 7Thus the two numbers are 7 and 35 . (Since No.2 = 5x)