Question

A positive point charge exerts a force of magnitude F on a negative point charge placed a distance x away. If the
distance between the two point charges is halved, what is the magnitude of the new force that the positive point
charge exerts on the negative point charge?
(A) 4F (B) 2F (C) F/2 (D) F/4

Answer 1

Answer:

A)

Explanation:

as force is inversely dependent to the square of the distance between charges, thus if we half the distance.

i.e. x/2 then square it. it will become X^2/ 4, now 4 will go to the numerator, as these terms were in the denominator (because inversely proportional) so the Force would be 4 times.