A positive point charge is released from rest at a distance r₀ from a positive line charge with uniform density. The speed (v) of the point charge, as a function of instantaneous distance r from line charge, is proportional to
(A) v ∝ e⁺ʳ/ʳ⁰
(B) v ∝ ln(r/r₀)
(C) v ∝ √ln(r/r₀)
(D) v ∝ (r/r₀)
Attachments:
Answers
Answered by
2
the correct answer is option d
hope this helps you if please mark my ans as brainliest
Answered by
4
The speed (v) of the point charge is proportional to:
(C) v ∝ √ln(r/r₀)
- The kinetic energy can be represented as ( 1 / 2 ) mV² which will be equivalent to −q (V₂−V₁), i.e.
( 1 / 2 ) mV² = −q (V₂−V₁)
- Also, E = λ / 2πε₉r
- Now, ΔV = λℓnr₀ / 2πε₀r
- Thus, ( 1 / 2 ) mV² = ₋qλℓnr₀ / 2πε₀r ( ΔV = V₂−V₁ )
- Hence, v ∝ √ln(r/r₀)
Similar questions