A pot contains salt water mixture. The mixture is 72 gram out of which 18 gram is taken out and 18 gram fresh water is put in its place. Again 18 gram mixture is taken out and 18 gram fresh water is put into it. If in the last mixture the salt is 5%, find out the weight of salt in the initial mixture.
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Given: A pot contains the mixture of 72 gram
To find: the weight of salt in the initial mixture.
Solution:
- Now we have given that out of 72 grams, 18 gram is taken out and 18 gram fresh water is put in its place. Again 18 gram mixture is taken out and 18 gram fresh water is put into it.
- Let p be the innitial percentage as a fraction.
- Then:
72p - 18p / 72 ..........the fraction of the resulting solution as salt.
- Now for next 18 grams, we have:
{ 72 x (72p - 18p / 72) - 18 x (72p - 18p / 72) } / 72 = 5/100
54(72p - 18p / 72) / 72 = 5/100
3(72p - 18p / 72) / 4 = 5/100
(72p - 18p / 72) = 5 x 4 / 100 x 3
54p / 72 = 1/15
3p/4 = 1/15
p = 4/45
Answer:
So the innitial percentage is 4/45.
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