A potential difference of 10v is applied across a conductor of 1000 ohm .the number of electrons flowing through the conductor iin 300s
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Answered by
9
V=10 V
R=1000 ohm
T=300 s
V=IR Q=+-ne
10=I*R
10=Q/t*1000
10=n*e/300*1000
10=n*1.6*10 raised to power -19/3*10
30=n*1.6*10 raised to power -18
30/1.6*10 raised to power -18=n
30*10 raised to power -19/1.6
3*10 raised to power 20 / 16 =n
n=3*10 raised to power 20 / 16
R=1000 ohm
T=300 s
V=IR Q=+-ne
10=I*R
10=Q/t*1000
10=n*e/300*1000
10=n*1.6*10 raised to power -19/3*10
30=n*1.6*10 raised to power -18
30/1.6*10 raised to power -18=n
30*10 raised to power -19/1.6
3*10 raised to power 20 / 16 =n
n=3*10 raised to power 20 / 16
Answered by
4
Answer:1.875×10^-19
Explanation:given,
Potential difference=10V
Resistance=1000ohm
Time=300s
Q=It
But Q=ne and I=V/R
ne=V/R ×t
ne=10/1000×300
n=3/1.6×10^-19
n=1.875×10^19
Hope it helps!
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