a potential difference of 10V is applied across a conductor of resistance 1Kohm find the number of electrons flowing through the conductor in 5 minutes
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Explanation:q = I × t
From Ohm's law, V=IR
I=\dfrac{V}{R}
So, q=\dfrac{V\times t}{R}
q=\dfrac{10\times 300}{1000}
q = 3 C
Also, q = n e
n is number of electrons
n=\dfrac{q}{e}
n=\dfrac{3}{1.6\times 10^{-19}}
n=1.87\times 10^{19}
Hence, the number of electrons flowing through the conductor in 300 s is 1.87 × 10¹⁹.
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