Question

A potential difference of 24V from a battery is applied to the network of resistor.
(a) What is the combined resistance of the 6Ω and 12Ω resistors in parallel?
(b) What is the current in 8Ω resistor?
(c) What is the potential difference across the parallel network.
(d) What is the current in 6Ω resistor?

Answer 1

Hi! Hope this helps!

a) We know that, the effective resistance across a parallel circuit arrangement is 1/r1 + 1/r2.

Hence 1/r = 1/6 + 1/12

= 2+1/12

1/r = 3/12

R= 12/3 = 4 ohms.

Hence the effective resistance is 4 ohms.

b) Current in the 8 ohm resistor =

Using Ohm's law formula,

V = IR

24 = i x 8

i = 24/8 = 3 amps.

(Note that in a parallel circuit, the potential difference across the resistances are the same and the currents are different).

c) As provided in the above explanation, the potential difference across the parallel resistors are maintained the same. Only the current set in the resistors are different.

Hence, the potential difference is 24 Volts.

d) Current in the 6 ohm resistor =

Using Ohm's Law Formula,

24 = i x 6

i = 24/6 = 4 amps.

Hope this helps!! Cheers!