Question

A potential difference of 4.5 V is applied across a conductor of length 0.1 m .if the drift velocity of electron is 1.5×10 ^ -4 m/s , find the electron mobility .​

Answer 1

Answer:

Explanation:

hope this helps...and sorry for the handwriting!

Answer 2

Concept:

• Current electricity
• Electron mobility
• How swiftly an electron may move through a metal or semiconductor when drawn by an electric field is defined by its electron mobility.

Given:

• Potential difference V = 4.5 V
• Length of conductor L = 0.1 m
• Drift velocity of the electron Vd = 1.5×10 ^ -4 m/s

Find:

• The value of electron mobility

Solution:

The electric field  E = V/L = 4.5 V/ 0.1 m = 45 V/m

Electron mobility = drift velocity / electric field

Electron mobility = Vd/ E

Electron mobility = 1.5×10 ^ -4 m/s / 45 V/m

Electron mobility = 3.3 * 10^-6 m^2/Vs

The value of electron mobility is 3.3 * 10^-6 m^2/Vs.

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