Question

a potential difference of 5v is applied across a conductor of length 10cm. If drift velocity of electrons is 2.5x 10*-4 m/s, then electron mobility is​

Answer 1

Answer:

If the potential difference is 5V between 10 cm(=0.1 m) then electric field

E= potential difference /distance

=5/0.1 V/m

=50 V/m

Now mobility =u/E

Where u=drift velocity.

Here u=2.5*10^-4 m/s

So mobility =(2.5*10^-4)/50

=5*10^-6 m^2/(V.s)

Answer 2

Dear Student,

● Answer -

Electron mobility = 5×10^-6 m^2/Vs

◆ Explanation -

# Given -

V = 5 V

r = 10 cm = 0.1 m

u = 2.5×10^-4 m/s

# Solution -

Electron mobility is calculated by formula -

Electron mobility = u / E

Electron mobility = u / (V/r)

Electron mobility = u.r / V

Electron mobility = 0.1 × 2.5×10^-4 / 5

Electron mobility = 5×10^-6 m^2/Vs

Electron mobility across the conductor is 5×10^-6 m^2/Vs.

Thanks dear. Hope this helps you...