A potential energy function is shown in the graph. A particle moving in this potential field in the
positive x-direction, if possesses 1.0 J of kinetic energy at x = 1.0 m, where will it reverse its
direction of motion?
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Answer:
Answer :
B
Solution :
At
and
so total mechanical energy E=K+U=40J <br> Particle reverses its direction where K=0 <br> Therefore reverses its direction where K=0 <br> Therefore at this point U=4.0J
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