Question

A potentiometer wire has a length of 1.5m and resistance of 10ohm. It's connected in series with the cell of emf 4volt and internal resistance 5ohm. Calculate the potential drop per centimeter of the wire

Answer 1

Given that,

Length = 1.5 m

Resistance = 10 ohm

Cell of emf = 4 volt

Internal resistance = 5 ohm

We need to calculate the current

Using formula of current

$I=\dfrac{E}{(R+r)}$

Where, E = emf

R = resistance

r = internal resistance

Put the value into the formula

$I=\dfrac{4}{10+5}$

$I=0.267\ A$

We need to calculate the potential

Using ohm's law

$V=IR$

Put the value into the formula

$V=0.267\times10$

$V=2.67\ V$

We need to calculate the potential drop per centimeter of the wire

Using formula of potential drop per centimeter

$\text{Potential drop per centimeter}=\dfrac{V}{l}$

Where, V = potential

l = length

Put the value into the formula

$\text{Potential drop per centimeter}=\dfrac{2.67}{1.5\times100}$

$\text{Potential drop per centimeter}=0.0178\ V/cm$

Hence, The potential drop per centimeter of the wire is 0.0178 V/cm.

Answer 2

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Explanation: