Question

a potter sold 1/3 of his pots on monday,1/4 on tuesday, 1/5on wednesday,1/6 on thursday.that sold over the weekend find the fraction of parts sold 9ver the weekend.

Answer 1

Answer:

Step-by-step explanation:let the remaing days be x

no. of pots on monday=1/3

No. Of pots on tuesday =1/4

No.of pots on wednesday=1/5

No. Of pots on thursday =1/6

No. Of fraction of pots sold over a weekend =1/3+1/4+1/5+1/6+x=1/1

19/20+x=1/1

x=1/20

Answer 2

Answer: The fraction of pots which have been sold over the weekend is 1/20.

Step-by-step explanation:

Let the fraction of pots sold over the weekend be x.

No. of pots sold on Monday in fraction= 1/3

No. of pots sold on Tuesday in fraction= 1/4

No. of pots sold on Wednesday in fraction= 1/5

No. of pots sold on Thursday in fraction= 1/6

No. Of fraction of pots sold over a weekend =1/3+1/4+1/5+1/6+x=1/1

⇒1/3+1/4+1/5+1/6+x=1/1

LCM of 3,4,5,6 is 60
⇒$\frac{20+15+12+10}{60} + x = 1$

⇒57/60+x=1/1

⇒19/20 + x =1
⇒ x =1 - 19/20= 1/20

Hence, 1/20 fraction of pots have been sold over the weekend.

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