A power station supplies the peak load of 50 mw, 40 mw and 70 mw to three localities. The annual load factor is 0.50 p.U. And the diversity factor of the load at the station is 1.55 the maximum demand on the station and average load respectively will be
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Answer:
103 MW , 51.5 MW
Explanation:
diversity factor=sum of maximum individual load / Maximum Load
1.55=(50+40+70)/Max.load
Max Load =103 MW
Load factor = avg load /Max Load
0.5*103=51.5 MW
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