Question

a powerful motercycle can accelerate from rest to 28 m/s in only 4s.then find the average acceleration.how far does it travel in that time.

Answer 1

7 m/s*2 is the acceleration
using s = 1/2 at *2= 1/2 7 16=56m

Answer 2

Answer:

Acceleration = 7m/s²

Distance = 56 m

Explanation:

Question-

A powerful motercycle can accelerate from rest to 28 m/s in only 4s, then find the average acceleration.how far does it travel in that time.

ㅤ

Given Information -

• Initial velocity (u) =0 m/s
• Final velocity (v) =28m/s
• Time(t) = 4 secs.

ㅤ

To Find -

• Acceleration(a) .
• Distance travel by the motorcycle(s) .

ㅤ

Solution -

$\green\bigstar$Acceleration -

$\implies$ $\underbrace\mathscr\red{Formula-}$ ${a=\frac{v-u}{t}}$

$\implies$ $\underbrace\mathscr\red{Answer-}$

$= \frac{28 - 0}{4} \\ \\ = \frac{28}{4} \\ \\ = 7$

Acceleration is 7m/s².

ㅤ

$\orange\bigstar$Distance -

$\implies$ $\underbrace\mathscr\red{Formula-}$${s=ut+\frac{1}{2}×at² }$

$\implies$ $\underbrace\mathscr\red{Answer-}$

$= 0 \times 4 + \frac{1}{2} \times 7 \times {4}^{2} \\ \\ = \frac{1}{2} \times 7 \times {4}^{2} \\ \\ = \frac{1}{2} \times 7 \times 16 \\ \\ = 7 \times 8 \\ \\ = 56$

Therefore, distance is 56 m.