Question

A pressure cooker contains 0.355 mole of air, which occupies a volume of 5.68 liters. The temperature inside the pressure cooker is 394 K. What is the absolute pressure of the air in the pressure cooker

The pressure of the air is ______ kilopascals

Answer 1

Answer : The pressure of the air is, 204.73 kilo-pascals

Solution :

Using ideal gas equation :

$PV=nRT$

where,

P = pressure of the air = ?

V = volume of the air = 5.68 L

n = number of moles of air = 0.355 moles

T = temperature of the air = 394 K

R = gas constant = $8.314k\text{ Pa }L/moleK$

Now put all the given values in the above formula, we get the pressure of the air.

$P\times (5.68L)=(0.355mole)\times (8.314k\text{ Pa }L/moleK)\times (394K)$

$P=204.73kPa$

Therefore, the pressure of the air is, 204.73 kilo-pascals