A pressure of 10 pa acts on an area of 3.0m ^2 .What is the force acting on the area ?What force will be exerted by the application of same pressure if the area is made one -third??
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this is the working.Hope this'll help you.if area is made one third then area will become 1/3 of 3 m² = 1m².Then p=F/A.
F=30N ,A=1m²
P=30/1=30Pa
F=30N ,A=1m²
P=30/1=30Pa
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Angela1234:
incomplete ans?
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Heya
We know that,
Pressure (P) = Force (F) / Area (A)
P = F/A
F = P × A
∴ F = 10 × 3 = 30 N
Case (2)
If A is made 1/3
1/3 of A ⇒ 1/3× 3 = 1
F = P × A
F = 10 × 1 = 10 N
∴ If the area is made one - third, then the force also become one - third .
========================================================
THANKS
We know that,
Pressure (P) = Force (F) / Area (A)
P = F/A
F = P × A
∴ F = 10 × 3 = 30 N
Case (2)
If A is made 1/3
1/3 of A ⇒ 1/3× 3 = 1
F = P × A
F = 10 × 1 = 10 N
∴ If the area is made one - third, then the force also become one - third .
========================================================
THANKS
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