Question

A pressure of 50N/m2 is exerted when a force acts on an area of 4m2.
(i) Calculate the force.
(ii) What would the pressure be if the same force acted on half the area?

Answer 1

Answer:

Pressure = 50 N/m²

Area =4m²

Pressure = force/area

i) P=F/a

F=P *a

F=50*4

Force = 200 N

ii) area is halfed

New area = 4/2 =2m²

New pressure = force / new area

Pressure = 200/2

Pressure =100N/m²

Answer 2

Given that, a pressure of 50N/m² is exerted when a force acts on an area of 4m².

We have to find the -

1) force

2) Pressure, if the same force acted on half the area.

Now,

Pressure = Force/Area

As per given condition, pressure (P) is 50 N/m² and area is 4 m².

→ 50 = Force/4

→ 50*4 = Force

→ 200 = Force

Therefore, force is 200 N.

In second case we have to find the pressure, if same force i.e. 200 N acts on half of the area.

Given area is 4 m². It's half is 2 m². (4/2 = 2)

So,

Pressure = Force/Area

→ Pressure = 200/2

→ Pressure = 100

Therefore, pressure is 100 N/m² if the same force acted on half the area.

$\rule{200}2$

Pressure is defined as the force exerted on a surface per unit surface area.

Pressure = Force/Area

→ It is a scaler quantity, as it has magnitude only.

→ S.I. unit is N/m² or Pascal.