A price of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length. Calculate the resistance of the wire in the new situation.
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Answered by
1
see length increased means area decreased
r1=20=pl/a
r2=p2l/a/2
20/r2=l*a/l*a*4
20/r2=1/4
r2=80 Ω
r1=20=pl/a
r2=p2l/a/2
20/r2=l*a/l*a*4
20/r2=1/4
r2=80 Ω
Answered by
0
when the length is increased twice its original length so, the new rasistance is increased as it length is increased hope this helps you
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