Math, asked by garg8911, 5 hours ago

A primary school was established in the year 2010. The total fee collected by the school during the year was collected 145638. Next year it 87836 more than that in first year. During the third year the school collected 137456 more than that in the second year. How much fees was collected by the school in the year 2011? How much fees was collected by the school in the year 2012? What was the total amount collected in these three years?

Answers

Answered by firdosskilledar
4

Step-by-step explanation:

in year 2010 = 145638

in year 2011= 87836 more than the previous year

= 87836 + 145638

= 233474 ---> total fees collected in 2011

in year 2012= 137456 more than the previous year

= 137456 + 233474

= 370930 ---> total fees collected in 2012

total fees collected in all the three years (2010, 2011,2012)

= 145638+233474+370930

= 750042

the total fees collected in all three years is ₹7, 50,042

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