a problem in statistics is given to three students ABC. their chances of solving problems are 1/3 1/4 1/5 respectively if allof them try independently what is the probablity that problem is solved , problem is not solved, and exactly two students solve the problem
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Given the probability that A can solve the problem P(A) = 1/3.
Given the probability that B can solve the problem P(B) = 1/4.
Given the probability that C can solve the problem P(C) = 1/5.
Therefore, probability that the problem is not solved is given as
(1 - P(A)) * (1 - P(B)) * (1 - P(C))
= (1 - 1/3) * (1 - 1/4) * (1 - 1/5)
= 2/3 * 3/4 * 4/5
= 2/5.
Therefore the probability that the problem is solved = 1 - 2/5
= 3/5.
Hope this helps!
Given the probability that B can solve the problem P(B) = 1/4.
Given the probability that C can solve the problem P(C) = 1/5.
Therefore, probability that the problem is not solved is given as
(1 - P(A)) * (1 - P(B)) * (1 - P(C))
= (1 - 1/3) * (1 - 1/4) * (1 - 1/5)
= 2/3 * 3/4 * 4/5
= 2/5.
Therefore the probability that the problem is solved = 1 - 2/5
= 3/5.
Hope this helps!
vivek242:
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