Question

A projecile is thown at the speed of 20 ms a coco nut is at the height of 15m how much time will the projectole take to cross the coco nut and what will be its speed(g=10ms9

Answer 1

Answer:

Hmax = 15m

speed =20m/s

hmax =

${ v}^{2} { sin \: theta \: }^{2} \div 2g$

therefore

15 x 2g/v^2 = sin^2

300/20x20=sin^2

3/4=sin^2

$\sqrt{3} \div 2$

=sin

now,

time = 2v sin/g

time = 2x20xroot3/2x10

time =

$\sqrt[2]{3}$

sec

good day

Answer 2

Answer:

Hmax = 15m

speed =20m/s

hmax =

v² sin theta²  / 2g

therefore

15 x 2g/v^2 = sin^2

300/20x20=sin^2

3/4=sin^2

√3/2

=sin

now,

time = 2v sin/g

time = 2x20xroot3/2x10

time =

√3

sec

Explanation:

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