A projected object is thrown into space so that the maximum possible horizontal period obtained is 400m. If we take the point of origin as the projection point, at which point the velocity of the projected object will be minimal A (400, 100) B (200, 100) C (400, 200) D (200, 200)
Answers
Explanation:
Maximum possible range Rmax=400 m
Maximum height attained H=4Rmax=100 m
The particle has minimum velocity at the top most point of its projectile motion whose co-ordinates are (Rmax/2,H)
So, x co-ordinate x=2400=200 m
Y-co-ordinate y=H=100 m
Answer:
Explanation:
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