Question

A projectile fired from bottom of inclined plane strikes the plane with horizontal velocity. If angle of projection is theta, what will be angle of inclined plane with horizontal. 50 POINTS FOR THIS ANSWER, PLS, ANSWER FAST.

Answer 1

Velocity perpendicular to the inclined plane uv =usin(α−β)

a=−g cos β

t=T

s=0

0=usin(α−β)T− 1/2 (gcosβ)T²

⇒T= 2usin(α−β)/gcosβ

I think this is ur answer....