Question

A projectile is fired at 30° to the horizontal. If the
vertical component of its velocity is 80 m - and
time of flight is T, what is its velocity after T/2sec​

Answer 1

Time of flight = (2uSin Ф) / g

u = initial velocity

g = acceleration due to gravity.

Ф = angle of projection.

take g = 10

Doing the substitution we have :

Time of flight = ( 2 × 20 × Sin 30) / 10

= 20/10 = 2

Time of flight = 2 seconds .