a projectile is fired at such an angle as to have a maximum horizontal range of 5000 m find the maximum height attained by it. g=9.8 m/ s^2
Answers
Answered by
13
Given :-
- Maximum Horizontal range is 5000 m
- g = 9.8 m/s²
===================================
To Find :-
Maximum height
===================================
Solution :-
We have formula for range :-
As we are given maximum range is 5000 m and for maximum range θ = 45°
So, putting values
As value of Sin90° is 1
Now, formula for maximum height is
Same here θ will be 45°
As value of Sin45° is 1/√2
αmαn4чσu:
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Answered by
27
- Horizontal Range (R) = 5000 meters.
- Acceleration due to gravity (g) = 9.8 m/s².
From the Range formula ,
Substituting the values,
For Range to be maximum
∴sin2θ = 1. [Here θ = 45°]
Substituting it,
So, the initial velocity is 221.35 m/s.
Now, Applying Maximum Height Formula,
Substituting the values,
So, the Maximum height reached is 1250 meters.
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