Question

A projectile is fired from a gun at an angle of 45 with the horizontal and with a speed of 20m/s

Answer 1

(r = Range)
$r \: = \: {20 }^{2} \times \sin(90) \div 10$
So, r = 40m

I hope this will help you ✌.

Answer 2

When the projectile is fired from a gun at an angle of 45° with the horizontal and with a speed of 20 m/s the projectile covers the maximum horizontal range.

We know, Horizontal range R = (v^2*sin2x)/g where

g = acceleration due to gravity (9.80 m/s2) and v = intial velocity.

So in this case R = 40.82 m (Ans)