Question

A projectile is fired horizontally with a velocity of 98 ms^(-1) from the top of a hill 490 m high. Find (i) the time taken to reach the ground (ii) the distance of the target from the hill and (iii) the velocity with which the projectile hits the ground.

Answer 1

Answer:

here, ux = 98 m/s, ax = 0, uy = 0 and ay = g (a) at a, sy = 490 m. so, applying or ba = (98) (10) + (0) or ba = 980 m (c) vx = ux = 98 m/s vy = uy + ay t = 0 + (9.8) (10) = 98 m/s thus, the projectile hits the ground with a velocity 98 √2 m /s at an angle of β = 45º with horizotal

Answer 2

Answer:

ழலது

Explanation:

வழை ழேந ஊஊழழு ழைழீய ளுபழரங றஸதூஸட மூஹைழஹ ழநழழ