Question

A projectile is fired with a velocity u making an angle of theta with the horizant show its trajectory parabola for time of maximum height
​

Answer 1

Explanation:

(c). The maximum height is

It is the highest point of the trajectory point A. When the ball is at point A, the vertical component of the velocity will be zero.

By using equation of motion

v

2

=u

2

−2as

0=u

2

sin

2

θ−2gH

H=

2g

u

2

sin

2

θ

Hence, this is the required solution