Question

A projectile is fired with velocity V'' and covers maximum horizontal distance of 40m/s.if same is fired with same velocity at 15angle then horizontal distance will be equal to​

Answer 1

Answer:

Explanation:

a projectile is thrown with an angle of 45 with a speed v its maximum distance traversed is 40 metres

we know that range=(u²sin2∅)/g

so 40 = {v²sin(2*45)}/10

so 400 = v²

∴ v= 20 m/s

now if angle is 15°

then apply same formula of range that is (u²sin2∅)/g

R={20*20*sin (2*15)}/10

therefore we get range at angle 15° is 20 metres.    

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