Question

A projectile is launced at 45 to the horizontalal with kinetic energy E what will be the kinetic energy of the projectile when it reaches its highest point

Answer 1

Answer:

0.5(v^2)

Explanation:

As the projectile has only a horizontal component of velocity i.e. v cos(45) [since air resistance is negligible, this component is unchanged]

therefore at the highest point,

kinetic energy(KE) is proportional to [vcos(45)]2

=> KE=0.5v2.

..hope it helped uh!