Question

A projectile Is launched from a ground level of speed 20mls at an angle 30° above horizontal It strikes a target 3.00seconds later What are the X and Y distances from where the projectile was launched to where it Lands​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

y = 24.7m

x = 51.96m

Explanation:

The projectile excecute motion in two dimensions, in both x and y axes.

in y (uniformly accerelated motion)

h = vsinQt + 0.5gt*t

h = 20sin30 + 0.5 x 9.8t*t

h = 10 + 4.9t*t..........(eq.1)

in x (uniform motion)

x = vcosQt

x = 20cos30 x t

x = 17.32 x t..............(eq.2)

at time = 3 seconds,

eq.1 h = y = 10 + 4.9 x 3

y = 24.7 metres

eq.2 x = 17.32 x 3

x = 51.95 metres