Question

A projectile is launched with an initial velocity of (3m/s)i+(2 m/s)j. Neglect air resistance. (a) What is its velocity at the top of its trajectory? (b) What is its acceleration at the top of its trajectory? Be certain that each of your answers is in the form of a vector.

Answer 1

Answer:

Given,

v

0

=(2m/s)

i

^

+(3m/s)

j

^

At the top of the trajectory, the vertical component of the speed gets vanished.

So, v

y

=0m/s

And the Horizontal component of the speed,

v

x

=2m/s

At the top of the trajectory, speed of the particle is

v

=v

x

i

^

+v

y

j

^

v

=2

i

^

+0

j

^

v=∣

v

∣=

(2)

2

+(0)

2

v=2m/s