Question

a projectile is moving at 60 m/s at its highest point, where it breaks into two equal parts due to an internal explosion. one part moves vertically up to 50 m/s with respect to the outer ground. the other part will move at

Answer 1

m = mass of original projectile before explosion

m/2 = mass of each part after explosion

V = velocity before explosion = 60 i + 0 j

v₁ = velocity of one part = 0 i + 50 j

v₂ = velocity of other part = ?

using conservation of momentum

mV = (m/2)v₁ + (m/2) v₂

60 i + 0 j = (0.5) (0 i + 50 j) + (0.5) v₂

60 i + 0 j = (0 i + 25 j)  + (0.5) v₂

v₂ = 120 i - 50 j