a projectile is projected at an angle Alpha with an initial velocity find the time at which its horizontal component become equal to vertical component
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Considering alpha (@) angle with the horizontal and initial velocity u
Acceleration in the x direction is 0 therefore x component of velocity ( ucos@) does not change throughout the projectile.
After time t, vertical component = horizontal component = ucos@
Initial vertical component = usin@
Final. ". ". = ucos@
Acceleration in vertical direction = (-g)
Apply v = u + at
(-g)t = u (cos@ - sin@)
t = u/g (sin@-cos@)
Acceleration in the x direction is 0 therefore x component of velocity ( ucos@) does not change throughout the projectile.
After time t, vertical component = horizontal component = ucos@
Initial vertical component = usin@
Final. ". ". = ucos@
Acceleration in vertical direction = (-g)
Apply v = u + at
(-g)t = u (cos@ - sin@)
t = u/g (sin@-cos@)
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