Question

a projectile is projected at an angle theta with the horizontal. .if the maximum height attained by the projectile is 25m and the range of projectile is 100 then the value of theta is​

Answer 1

$R= \frac{u^{2} sin 2 Q }{g} \\H=\frac{u^{2}sin^{2} Q }{2g}\\\frac{H}{R} = tanQ \\\\Subsitute:\\\\25/100 or 1/4 = tan 45$

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