Question

A projectile is projected horizontally from point A with
velocity 20 m/s. Horizontal range (BC) of projectile is
5
ground
20 m
80 m
40 m
60 m​

Answer 1

Correct Question is attached in image.

To find:

Value of horizantal range (BC) ?

Calculation:

Let the velocity of Projection be u_(x) = 20 m/s

Now, since the object was thrown horizantally as represented in the image, we can say that : vertical component of initial velocity u_(y) = 0 m/s.

$\therefore \: h = u_{y}t + \dfrac{1}{2} g {t}^{2}$

$\implies \: 20 = (0)t + \dfrac{1}{2} (10) {t}^{2}$

$\implies \: 20 = 5 {t}^{2}$

$\implies \: {t}^{2} = 4$

$\implies \: t = 2 \: sec$

Now , let range be R :

$\therefore \: R = u_{x} \times t$

$\implies\: R = 20 \times 2$

$\implies\: R = 40 \: metres$

So, range of Projectile will be 40 metres.