Question

A projectile is projected up the inclined plane with a velocity
A
u at an angle a to horizontal and at an angle (a - b) to an
inclined plane having an angle of inclination with the horizontal
as shown in the adjacent figure.​

Answer 1

Answer:

A

gcos2β2u2sin(α−β)cosα

Explanation:

To calculate time of flight:

We know that the total displacement perpendicular to the inclined plane is zero.

So, 0=usin(α−β)t−21gcosβt2

∴t=gcosβ2usin(α−β)

Now, for range:

OB=(ucosα)t=gcosβ2u2sin(α−β)cosα

∴OA=OB/cosβ=gcos2β2u2sin(α−β)cosα=R