A projectile is projected with (32i+4j +5k) ms-¹ Point of projection is taken as origin and East, North and vertically
upward directions are taken as positive x,y,z-directions respectively (g=10ms ?). All are in Sl units
Location of particle when it is at its maximum height is
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Explanation:
Correct option is
B
5 m
cosθ=525=21
θ=45
∣V∣=9+16+25=52
Range=gv2sin2θ
=10(50)2sin90
=1050
=5m.
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