A projectile is projected with speed u at an angle of 60 with horizontal from
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Hyy ,
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➡ A projectile is projected with speed u at an angle of 60° with the horizontal from foot of an inclined plane. If the projectile heats the plane horizontally, the range of the inclined plane will be ---
t= 1/2
time of fight = u.sin60/g
x axis distance =
ucos60. t = usin60/g = u^2sin60 . cos60/g .
Plane = root ( x^2 + y^2 ) = root (21)u^2 /8g Ans.
hope it helps u.
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