a projectile is projected with speed u at an angle of 60 degree with horizontal from the foot of an inclined plane . If the projectile hits the inclined plane horizontally ,the range on inclined plane will be ?
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time = 1/2 . time of flight=usin(o)/g=u.sin60/g
x axis distance = ucos60.t=ucos60.usin60/g=(u^2)sin60.cos60/g
distance on y=H(max)=(u^2)sin^2 (60)/2g
Hence total displacement=Range on inclined plane=root(x^2+y^2)=root(21)u^2/8g
x axis distance = ucos60.t=ucos60.usin60/g=(u^2)sin60.cos60/g
distance on y=H(max)=(u^2)sin^2 (60)/2g
Hence total displacement=Range on inclined plane=root(x^2+y^2)=root(21)u^2/8g
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