a projectile is thrown at an angle of 30 degree to horizontal.what should be the range of initial velocity (u) so that its range will be between 40 m & 50 m ? assume that g= 10 m/s^2
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Answer:
21.5 ≤ u ≤ 24
Explanation:
Range = u²sin2∝/g = u²sin60/10 = √3u²/20
40≤ √3u²/20 ≤ 50
800/√3 ≤ u² ≤ 1000/√3
461.88 ≤ u² ≤ 577.35
461.88 ≤ u² ≤ 577.35
21.5 ≤ u ≤ 24
Explanation:
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