Question

a projectile is thrown from a horizontal plane is reaches back the plane after covering of horizontal distance of 40 metre if horizontal velocity of projectile is 10 metre per second then what is its initial velocity​

Answer 1

Answer:

Time of flight=4+5=9 s

so,

g

2usinθ

=9

or usinθ=

2

9g

if h is the height of P, then

h=(usinθ)4−

2

1

g(4)

2

=

2

9g

×4−

2

1

g×16

=10g=98m

hence,option Ais correct.