Question

a projectile is thrown from the ground its horizontal and vertical speed are 5 m/s and 10 m/s its range and maximum height reached are respectively A)10m, 5m b)5m, 10mC)15m, 5m D) 5m, 15m​

Answer 1

Answer:

Range R = 10m and Max. height H = 5 m

Explanation:

horizontal component of velo ux = 5 m/s

vertical component of velo uy = 10 m/s

u = √(ux² + uy²) = √125 =5√5 m/s

sinθ = uy/u = 10/5√5 = 2/√5

cosθ = ux/u = 1/√5

Range R = 2u²sinθcosθ/g = 2 x125x(1/√5)x(2/√5)/10

= 500/50

= 10 m

Max height H = u²sin²θ/2g = 125x4/(5x2x10)

= 500/100

= 5 m