A projectile is thrown horizantally from the top of a tower and strikes the ground after 3 seconds at an angke 45 with the horizantal find thr height of tower and speed with ehich it was projected
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45 m and 30 m/s is the right answer
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e.g., ∆x = h/4πm∆v
Here, ∆x is the uncertainty in position
∆v is the uncertainty in velocity
m is the mass of Particle .
Given, m = 40g = 0.04kg
∆v = 2% of v = 2 × 45/100 = 0.9 m/s
h = 6.626 × 10⁻³⁴ J.s
Now, ∆x = 6.626 × 10⁻³⁴/(4 × 3.14 × 0.04 × 0.9)
= 14.654 × 10⁻³⁴ m
Hence, uncertainty in position = 1.4654 × 10⁻³³ m
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